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2000202211993 is a prime number
BaseRepresentation
bin11101000110110101010…
…101111010001010011001
321002012212112100021200011
4131012311111322022121
5230232403231240433
64130514043041521
7264336606164266
oct35066525721231
97065775307604
102000202211993
11701310004737
1228379b8102a1
1311680641443b
146cb4b68a26d
153706ab223cd
hex1d1b557a299

2000202211993 has 2 divisors, whose sum is σ = 2000202211994. Its totient is φ = 2000202211992.

The previous prime is 2000202211967. The next prime is 2000202212143. The reversal of 2000202211993 is 3991122020002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1992704903424 + 7497308569 = 1411632^2 + 86587^2 .

It is a cyclic number.

It is not a de Polignac number, because 2000202211993 - 25 = 2000202211961 is a prime.

It is a super-2 number, since 2×20002022119932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2000202211193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000101105996 + 1000101105997.

It is an arithmetic number, because the mean of its divisors is an integer number (1000101105997).

Almost surely, 22000202211993 is an apocalyptic number.

It is an amenable number.

2000202211993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2000202211993 is an equidigital number, since it uses as much as digits as its factorization.

2000202211993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

Adding to 2000202211993 its reverse (3991122020002), we get a palindrome (5991324231995).

The spelling of 2000202211993 in words is "two trillion, two hundred two million, two hundred eleven thousand, nine hundred ninety-three".