Base | Representation |
---|---|
bin | 11101000110110101010… |
… | …101111010001010011001 |
3 | 21002012212112100021200011 |
4 | 131012311111322022121 |
5 | 230232403231240433 |
6 | 4130514043041521 |
7 | 264336606164266 |
oct | 35066525721231 |
9 | 7065775307604 |
10 | 2000202211993 |
11 | 701310004737 |
12 | 28379b8102a1 |
13 | 11680641443b |
14 | 6cb4b68a26d |
15 | 3706ab223cd |
hex | 1d1b557a299 |
2000202211993 has 2 divisors, whose sum is σ = 2000202211994. Its totient is φ = 2000202211992.
The previous prime is 2000202211967. The next prime is 2000202212143. The reversal of 2000202211993 is 3991122020002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1992704903424 + 7497308569 = 1411632^2 + 86587^2 .
It is a cyclic number.
It is not a de Polignac number, because 2000202211993 - 25 = 2000202211961 is a prime.
It is a super-2 number, since 2×20002022119932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2000202211193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000101105996 + 1000101105997.
It is an arithmetic number, because the mean of its divisors is an integer number (1000101105997).
Almost surely, 22000202211993 is an apocalyptic number.
It is an amenable number.
2000202211993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2000202211993 is an equidigital number, since it uses as much as digits as its factorization.
2000202211993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 31.
Adding to 2000202211993 its reverse (3991122020002), we get a palindrome (5991324231995).
The spelling of 2000202211993 in words is "two trillion, two hundred two million, two hundred eleven thousand, nine hundred ninety-three".
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