Base | Representation |
---|---|
bin | 101101011110101101001101… |
… | …011100010100000101101011 |
3 | 222020012221022111202111001211 |
4 | 231132231031130110011223 |
5 | 202204131002112204323 |
6 | 1545224535003053551 |
7 | 60063062051426305 |
oct | 5536551534240553 |
9 | 866187274674054 |
10 | 200022221209963 |
11 | 58807a47339289 |
12 | 1a5257912112b7 |
13 | 877c025bb3229 |
14 | 37571acd08975 |
15 | 181d084d1670d |
hex | b5eb4d71416b |
200022221209963 has 2 divisors, whose sum is σ = 200022221209964. Its totient is φ = 200022221209962.
The previous prime is 200022221209957. The next prime is 200022221209999. The reversal of 200022221209963 is 369902122220002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200022221209963 - 217 = 200022221078891 is a prime.
It is a super-2 number, since 2×2000222212099632 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200022221209163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100011110604981 + 100011110604982.
It is an arithmetic number, because the mean of its divisors is an integer number (100011110604982).
Almost surely, 2200022221209963 is an apocalyptic number.
200022221209963 is a deficient number, since it is larger than the sum of its proper divisors (1).
200022221209963 is an equidigital number, since it uses as much as digits as its factorization.
200022221209963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 40.
Adding to 200022221209963 its reverse (369902122220002), we get a palindrome (569924343429965).
The spelling of 200022221209963 in words is "two hundred trillion, twenty-two billion, two hundred twenty-one million, two hundred nine thousand, nine hundred sixty-three".
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