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200022428481 = 366674142827
BaseRepresentation
bin1011101001001001000…
…1000000101101000001
3201010021220111011120220
42322102101000231001
511234121220202411
6231520010453253
720310512406111
oct2722221005501
9633256434526
10200022428481
11779134a0037
1232923134229
1315b28b72a75
14997707d041
15530a404b06
hex2e92440b41

200022428481 has 4 divisors (see below), whose sum is σ = 266696571312. Its totient is φ = 133348285652.

The previous prime is 200022428467. The next prime is 200022428539. The reversal of 200022428481 is 184824220002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200022428481 - 25 = 200022428449 is a prime.

It is a super-2 number, since 2×2000224284812 (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (200022428461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33337071411 + ... + 33337071416.

It is an arithmetic number, because the mean of its divisors is an integer number (66674142828).

Almost surely, 2200022428481 is an apocalyptic number.

It is an amenable number.

200022428481 is a deficient number, since it is larger than the sum of its proper divisors (66674142831).

200022428481 is an equidigital number, since it uses as much as digits as its factorization.

200022428481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66674142830.

The product of its (nonzero) digits is 16384, while the sum is 33.

Adding to 200022428481 its reverse (184824220002), we get a palindrome (384846648483).

The spelling of 200022428481 in words is "two hundred billion, twenty-two million, four hundred twenty-eight thousand, four hundred eighty-one".

Divisors: 1 3 66674142827 200022428481