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200032013131 = 533774188927
BaseRepresentation
bin1011101001001011010…
…1100100101101001011
3201010022120112010020221
42322102311210231023
511234131143410011
6231520552130511
720310660025516
oct2722265445513
9633276463227
10200032013131
1177918947135
1232926396a37
1315b2ab4a562
149978455d7d
15530b199971
hex2e92d64b4b

200032013131 has 4 divisors (see below), whose sum is σ = 203806202112. Its totient is φ = 196257824152.

The previous prime is 200032013123. The next prime is 200032013147. The reversal of 200032013131 is 131310230002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200032013131 - 23 = 200032013123 is a prime.

It is a super-2 number, since 2×2000320131312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200032013161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1887094411 + ... + 1887094516.

It is an arithmetic number, because the mean of its divisors is an integer number (50951550528).

Almost surely, 2200032013131 is an apocalyptic number.

200032013131 is a deficient number, since it is larger than the sum of its proper divisors (3774188981).

200032013131 is an equidigital number, since it uses as much as digits as its factorization.

200032013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3774188980.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 200032013131 its reverse (131310230002), we get a palindrome (331342243133).

The spelling of 200032013131 in words is "two hundred billion, thirty-two million, thirteen thousand, one hundred thirty-one".

Divisors: 1 53 3774188927 200032013131