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20003334134123 = 35633356136631
BaseRepresentation
bin1001000110001011000111…
…01000000001100101101011
32121211022002202020001211202
410203011203220001211223
510110213312014242443
6110313223240114415
74133123160501344
oct443054350014553
977738082201752
1020003334134123
1164124036a638a
1222b0944165a0b
13b213c9c87972
144d2248da10cb
1524a4ec92c7b8
hex123163a0196b

20003334134123 has 4 divisors (see below), whose sum is σ = 20003390627088. Its totient is φ = 20003277641160.

The previous prime is 20003334134111. The next prime is 20003334134131. The reversal of 20003334134123 is 32143143330002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20003334134123 - 218 = 20003333871979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20003334130123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27711983 + ... + 28424648.

It is an arithmetic number, because the mean of its divisors is an integer number (5000847656772).

Almost surely, 220003334134123 is an apocalyptic number.

20003334134123 is a deficient number, since it is larger than the sum of its proper divisors (56492965).

20003334134123 is an equidigital number, since it uses as much as digits as its factorization.

20003334134123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56492964.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 20003334134123 its reverse (32143143330002), we get a palindrome (52146477464125).

The spelling of 20003334134123 in words is "twenty trillion, three billion, three hundred thirty-four million, one hundred thirty-four thousand, one hundred twenty-three".

Divisors: 1 356333 56136631 20003334134123