Base | Representation |
---|---|
bin | 1011101001001101011… |
… | …1110111110001010001 |
3 | 201010100012102220120021 |
4 | 2322103113313301101 |
5 | 11234140444112423 |
6 | 231521512543441 |
7 | 20311126323346 |
oct | 2722327676121 |
9 | 633305386507 |
10 | 200041004113 |
11 | 77922a281a5 |
12 | 329293b1b81 |
13 | 15b2c977a72 |
14 | 99797167cd |
15 | 530bd7395d |
hex | 2e935f7c51 |
200041004113 has 16 divisors (see below), whose sum is σ = 213942059136. Its totient is φ = 186378382080.
The previous prime is 200041004099. The next prime is 200041004153. The reversal of 200041004113 is 311400140002.
It is not a de Polignac number, because 200041004113 - 221 = 200038906961 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200041004153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5182995 + ... + 5221447.
It is an arithmetic number, because the mean of its divisors is an integer number (13371378696).
Almost surely, 2200041004113 is an apocalyptic number.
It is an amenable number.
200041004113 is a deficient number, since it is larger than the sum of its proper divisors (13901055023).
200041004113 is a wasteful number, since it uses less digits than its factorization.
200041004113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41544.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 200041004113 its reverse (311400140002), we get a palindrome (511441144115).
The spelling of 200041004113 in words is "two hundred billion, forty-one million, four thousand, one hundred thirteen".
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