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2000420001433 = 72324375098469
BaseRepresentation
bin11101000111000010010…
…100101101011010011001
321002020102201011010121201
4131013002110231122121
5230233330010021213
64130551423034201
7264345162313030
oct35070224553231
97066381133551
102000420001433
11701411a38107
1228384073b961
1311683c589929
146cb6c57d717
153707ece26dd
hex1d1c252d699

2000420001433 has 16 divisors (see below), whose sum is σ = 2386573413120. Its totient is φ = 1639422582336.

The previous prime is 2000420001431. The next prime is 2000420001439. The reversal of 2000420001433 is 3341000240002.

It is not a de Polignac number, because 2000420001433 - 21 = 2000420001431 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2000420001433.

It is not an unprimeable number, because it can be changed into a prime (2000420001431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2156878 + ... + 2941591.

It is an arithmetic number, because the mean of its divisors is an integer number (149160838320).

Almost surely, 22000420001433 is an apocalyptic number.

2000420001433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2000420001433 is a deficient number, since it is larger than the sum of its proper divisors (386153411687).

2000420001433 is a wasteful number, since it uses less digits than its factorization.

2000420001433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5100936.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 2000420001433 its reverse (3341000240002), we get a palindrome (5341420241435).

The spelling of 2000420001433 in words is "two trillion, four hundred twenty million, one thousand, four hundred thirty-three".

Divisors: 1 7 23 161 2437 17059 56051 392357 5098469 35689283 117264787 820853509 12424968953 86974782671 285774285919 2000420001433