Base | Representation |
---|---|
bin | 1001000110001101000001… |
… | …00110100101100000011011 |
3 | 2121211101202001020112022011 |
4 | 10203012200212211200123 |
5 | 10110222410413322011 |
6 | 110313512543210351 |
7 | 4133160422233021 |
oct | 443064046454033 |
9 | 77741661215264 |
10 | 20004357167131 |
11 | 6412889121207 |
12 | 22b0b8a8a69b7 |
13 | b21530bca93c |
14 | 4d2304bc6711 |
15 | 24a55c65d621 |
hex | 1231a09a581b |
20004357167131 has 4 divisors (see below), whose sum is σ = 20649659011264. Its totient is φ = 19359055323000.
The previous prime is 20004357167033. The next prime is 20004357167191. The reversal of 20004357167131 is 13176175340002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20004357167131 - 243 = 11208264144923 is a prime.
It is a super-2 number, since 2×200043571671312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20004357167191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 322650922020 + ... + 322650922081.
It is an arithmetic number, because the mean of its divisors is an integer number (5162414752816).
Almost surely, 220004357167131 is an apocalyptic number.
20004357167131 is a deficient number, since it is larger than the sum of its proper divisors (645301844133).
20004357167131 is an equidigital number, since it uses as much as digits as its factorization.
20004357167131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 645301844132.
The product of its (nonzero) digits is 105840, while the sum is 40.
The spelling of 20004357167131 in words is "twenty trillion, four billion, three hundred fifty-seven million, one hundred sixty-seven thousand, one hundred thirty-one".
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