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20005106716433 is a prime number
BaseRepresentation
bin1001000110001110011010…
…10001111000111100010001
32121211110200021122120122102
410203013031101320330101
510110230424304411213
6110314115200450145
74133215123263656
oct443071521707421
977743607576572
1020005106716433
116413133233743
1222b1159919955
13b21620298237
144d237657bc2d
1524a5a336c158
hex1231cd478f11

20005106716433 has 2 divisors, whose sum is σ = 20005106716434. Its totient is φ = 20005106716432.

The previous prime is 20005106716393. The next prime is 20005106716447. The reversal of 20005106716433 is 33461760150002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19062017124049 + 943089592384 = 4366007^2 + 971128^2 .

It is a cyclic number.

It is not a de Polignac number, because 20005106716433 - 222 = 20005102522129 is a prime.

It is not a weakly prime, because it can be changed into another prime (20005106716333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10002553358216 + 10002553358217.

It is an arithmetic number, because the mean of its divisors is an integer number (10002553358217).

Almost surely, 220005106716433 is an apocalyptic number.

It is an amenable number.

20005106716433 is a deficient number, since it is larger than the sum of its proper divisors (1).

20005106716433 is an equidigital number, since it uses as much as digits as its factorization.

20005106716433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 38.

Adding to 20005106716433 its reverse (33461760150002), we get a palindrome (53466866866435).

The spelling of 20005106716433 in words is "twenty trillion, five billion, one hundred six million, seven hundred sixteen thousand, four hundred thirty-three".