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20005112013451 = 35693356047247
BaseRepresentation
bin1001000110001110011011…
…00110000110001010001011
32121211110200122121200210021
410203013031212012022023
510110230432133412301
6110314115510201311
74133215216305115
oct443071546061213
977743618550707
1020005112013451
116413136221444
1222b115b653237
13b21621401276
144d237715a3b5
1524a5a3a668a1
hex1231cd98628b

20005112013451 has 4 divisors (see below), whose sum is σ = 20005168417632. Its totient is φ = 20005055609272.

The previous prime is 20005112013449. The next prime is 20005112013511. The reversal of 20005112013451 is 15431021150002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20005112013451 - 21 = 20005112013449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20005112313451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27666691 + ... + 28380556.

It is an arithmetic number, because the mean of its divisors is an integer number (5001292104408).

Almost surely, 220005112013451 is an apocalyptic number.

20005112013451 is a deficient number, since it is larger than the sum of its proper divisors (56404181).

20005112013451 is an equidigital number, since it uses as much as digits as its factorization.

20005112013451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56404180.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 20005112013451 its reverse (15431021150002), we get a palindrome (35436133163453).

The spelling of 20005112013451 in words is "twenty trillion, five billion, one hundred twelve million, thirteen thousand, four hundred fifty-one".

Divisors: 1 356933 56047247 20005112013451