Base | Representation |
---|---|
bin | 1001000110001110011011… |
… | …00110000110110001011011 |
3 | 2121211110200122121211020022 |
4 | 10203013031212012301123 |
5 | 10110230432134002323 |
6 | 110314115510221055 |
7 | 4133215216315334 |
oct | 443071546066133 |
9 | 77743618554208 |
10 | 20005112015963 |
11 | 6413136223318 |
12 | 22b115b65478b |
13 | b21621402459 |
14 | 4d237715b28b |
15 | 24a5a3a674c8 |
hex | 1231cd986c5b |
20005112015963 has 2 divisors, whose sum is σ = 20005112015964. Its totient is φ = 20005112015962.
The previous prime is 20005112015909. The next prime is 20005112016163. The reversal of 20005112015963 is 36951021150002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20005112015963 - 218 = 20005111753819 is a prime.
It is not a weakly prime, because it can be changed into another prime (20005132015963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10002556007981 + 10002556007982.
It is an arithmetic number, because the mean of its divisors is an integer number (10002556007982).
Almost surely, 220005112015963 is an apocalyptic number.
20005112015963 is a deficient number, since it is larger than the sum of its proper divisors (1).
20005112015963 is an equidigital number, since it uses as much as digits as its factorization.
20005112015963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 35.
Adding to 20005112015963 its reverse (36951021150002), we get a palindrome (56956133165965).
The spelling of 20005112015963 in words is "twenty trillion, five billion, one hundred twelve million, fifteen thousand, nine hundred sixty-three".
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