Base | Representation |
---|---|
bin | 11101000111100101100… |
… | …011111101010000111011 |
3 | 21002021221220121012002001 |
4 | 131013211203331100323 |
5 | 230241032331413313 |
6 | 4131130222321431 |
7 | 264365631400126 |
oct | 35074543752073 |
9 | 7067856535061 |
10 | 2001011201083 |
11 | 701695725164 |
12 | 283986729277 |
13 | 116904bc39cb |
14 | 6cbc6cb53bd |
15 | 370b6b72add |
hex | 1d1e58fd43b |
2001011201083 has 2 divisors, whose sum is σ = 2001011201084. Its totient is φ = 2001011201082.
The previous prime is 2001011201071. The next prime is 2001011201149. The reversal of 2001011201083 is 3801021101002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2001011201083 - 29 = 2001011200571 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2001011201083.
It is not a weakly prime, because it can be changed into another prime (2001011201003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000505600541 + 1000505600542.
It is an arithmetic number, because the mean of its divisors is an integer number (1000505600542).
Almost surely, 22001011201083 is an apocalyptic number.
2001011201083 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001011201083 is an equidigital number, since it uses as much as digits as its factorization.
2001011201083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 2001011201083 its reverse (3801021101002), we get a palindrome (5802032302085).
The spelling of 2001011201083 in words is "two trillion, one billion, eleven million, two hundred one thousand, eighty-three".
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