Base | Representation |
---|---|
bin | 10010101000101111… |
… | …111010000101010011 |
3 | 1220122121020010121121 |
4 | 102220233322011103 |
5 | 311440304001042 |
6 | 13105401103111 |
7 | 1305614460205 |
oct | 225057720523 |
9 | 56577203547 |
10 | 20011000147 |
11 | 8539762656 |
12 | 3a65787a97 |
13 | 1b6ba597b8 |
14 | d7b94a775 |
15 | 7c1be0367 |
hex | 4a8bfa153 |
20011000147 has 2 divisors, whose sum is σ = 20011000148. Its totient is φ = 20011000146.
The previous prime is 20011000111. The next prime is 20011000213. The reversal of 20011000147 is 74100011002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20011000147 - 27 = 20011000019 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 20011000147.
It is not a weakly prime, because it can be changed into another prime (20011000547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005500073 + 10005500074.
It is an arithmetic number, because the mean of its divisors is an integer number (10005500074).
Almost surely, 220011000147 is an apocalyptic number.
20011000147 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011000147 is an equidigital number, since it uses as much as digits as its factorization.
20011000147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 16.
Adding to 20011000147 its reverse (74100011002), we get a palindrome (94111011149).
The spelling of 20011000147 in words is "twenty billion, eleven million, one hundred forty-seven", and thus it is an aban number.
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