Base | Representation |
---|---|
bin | 11101000111101010111… |
… | …011010110110010111011 |
3 | 21002022012011222200020221 |
4 | 131013222323112302323 |
5 | 230241223403033201 |
6 | 4131143200000511 |
7 | 264401103505042 |
oct | 35075273266273 |
9 | 7068164880227 |
10 | 2001101221051 |
11 | 70173151a529 |
12 | 2839b0900137 |
13 | 11691a751a6a |
14 | 6cbd4c29559 |
15 | 370bea054a1 |
hex | 1d1eaed6cbb |
2001101221051 has 2 divisors, whose sum is σ = 2001101221052. Its totient is φ = 2001101221050.
The previous prime is 2001101220997. The next prime is 2001101221069. The reversal of 2001101221051 is 1501221011002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2001101221051 - 215 = 2001101188283 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001101221151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000550610525 + 1000550610526.
It is an arithmetic number, because the mean of its divisors is an integer number (1000550610526).
Almost surely, 22001101221051 is an apocalyptic number.
2001101221051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001101221051 is an equidigital number, since it uses as much as digits as its factorization.
2001101221051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 2001101221051 its reverse (1501221011002), we get a palindrome (3502322232053).
The spelling of 2001101221051 in words is "two trillion, one billion, one hundred one million, two hundred twenty-one thousand, fifty-one".
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