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2001102000097 = 13115275587787
BaseRepresentation
bin11101000111101010111…
…110010100111111100001
321002022012020110020220111
4131013222332110333201
5230241224103000342
64131143224411321
7264401113231234
oct35075276247741
97068166406814
102001102000097
11701731a01872
122839b1016b41
1311691a965535
146cbd4d8d41b
15370beb0b217
hex1d1eaf94fe1

2001102000097 has 4 divisors (see below), whose sum is σ = 2016377588016. Its totient is φ = 1985826412180.

The previous prime is 2001101999957. The next prime is 2001102000167. The reversal of 2001102000097 is 7900002011002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2001102000097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2001102000197) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7637793763 + ... + 7637794024.

It is an arithmetic number, because the mean of its divisors is an integer number (504094397004).

Almost surely, 22001102000097 is an apocalyptic number.

It is an amenable number.

2001102000097 is a deficient number, since it is larger than the sum of its proper divisors (15275587919).

2001102000097 is a wasteful number, since it uses less digits than its factorization.

2001102000097 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15275587918.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 2001102000097 its reverse (7900002011002), we get a palindrome (9901104011099).

The spelling of 2001102000097 in words is "two trillion, one billion, one hundred two million, ninety-seven", and thus it is an aban number.

Divisors: 1 131 15275587787 2001102000097