Base | Representation |
---|---|
bin | 101101011111111111111001… |
… | …110011000100011001110110 |
3 | 222020112102111111200020012020 |
4 | 231133333321303010121312 |
5 | 202212104323110431402 |
6 | 1545333421354134010 |
7 | 60102354300416511 |
oct | 5537777163043166 |
9 | 866472444606166 |
10 | 200111012202102 |
11 | 58841670560921 |
12 | 1a53aa31121306 |
13 | 87875063a8c31 |
14 | 375b5d340dd78 |
15 | 182052ee788bc |
hex | b5fff9cc4676 |
200111012202102 has 32 divisors (see below), whose sum is σ = 404776326366720. Its totient is φ = 65948406195360.
The previous prime is 200111012202047. The next prime is 200111012202169. The reversal of 200111012202102 is 201202210111002.
200111012202102 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 473011918 + ... + 473434785.
It is an arithmetic number, because the mean of its divisors is an integer number (12649260198960).
Almost surely, 2200111012202102 is an apocalyptic number.
200111012202102 is an abundant number, since it is smaller than the sum of its proper divisors (204665314164618).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200111012202102 is a wasteful number, since it uses less digits than its factorization.
200111012202102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 946447108.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 200111012202102 its reverse (201202210111002), we get a palindrome (401313222313104).
The spelling of 200111012202102 in words is "two hundred trillion, one hundred eleven billion, twelve million, two hundred two thousand, one hundred two".
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