Base | Representation |
---|---|
bin | 1001000110011001100110… |
… | …00110101001010011011010 |
3 | 2121212001011122220121011012 |
4 | 10203030303012221103122 |
5 | 10110330223130341442 |
6 | 110320551012133522 |
7 | 4133516650406525 |
oct | 443146306512332 |
9 | 77761148817135 |
10 | 20011110012122 |
11 | 6415733a05639 |
12 | 22b23543072a2 |
13 | b22068c490c8 |
14 | 4d27859a7bbc |
15 | 24a805406582 |
hex | 1233331a94da |
20011110012122 has 4 divisors (see below), whose sum is σ = 30016665018186. Its totient is φ = 10005555006060.
The previous prime is 20011110012107. The next prime is 20011110012197. The reversal of 20011110012122 is 22121001111002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 17871680155081 + 2139429857041 = 4227491^2 + 1462679^2 .
It is a junction number, because it is equal to n+sod(n) for n = 20011110012097 and 20011110012106.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002777503029 + ... + 5002777503032.
Almost surely, 220011110012122 is an apocalyptic number.
20011110012122 is a deficient number, since it is larger than the sum of its proper divisors (10005555006064).
20011110012122 is a wasteful number, since it uses less digits than its factorization.
20011110012122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10005555006063.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 20011110012122 its reverse (22121001111002), we get a palindrome (42132111123124).
The spelling of 20011110012122 in words is "twenty trillion, eleven billion, one hundred ten million, twelve thousand, one hundred twenty-two".
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