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200111303113 is a prime number
BaseRepresentation
bin1011101001011110010…
…0000010100111001001
3201010112002201110122221
42322113210002213021
511234311443144423
6231532503414041
720312642003611
oct2722744024711
9633462643587
10200111303113
1177959682947
1232948a54321
1315b413bc6c7
149984bb5a41
15531310ce5d
hex2e979029c9

200111303113 has 2 divisors, whose sum is σ = 200111303114. Its totient is φ = 200111303112.

The previous prime is 200111303083. The next prime is 200111303167. The reversal of 200111303113 is 311303111002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119417242624 + 80694060489 = 345568^2 + 284067^2 .

It is a cyclic number.

It is not a de Polignac number, because 200111303113 - 225 = 200077748681 is a prime.

It is not a weakly prime, because it can be changed into another prime (200111303173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100055651556 + 100055651557.

It is an arithmetic number, because the mean of its divisors is an integer number (100055651557).

Almost surely, 2200111303113 is an apocalyptic number.

It is an amenable number.

200111303113 is a deficient number, since it is larger than the sum of its proper divisors (1).

200111303113 is an equidigital number, since it uses as much as digits as its factorization.

200111303113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 200111303113 its reverse (311303111002), we get a palindrome (511414414115).

The spelling of 200111303113 in words is "two hundred billion, one hundred eleven million, three hundred three thousand, one hundred thirteen".