Base | Representation |
---|---|
bin | 1001000110011001110010… |
… | …10001000111111010100001 |
3 | 2121212001102212111101011121 |
4 | 10203030321101013322201 |
5 | 10110330431114002431 |
6 | 110321005144412241 |
7 | 4133522344363666 |
oct | 443147121077241 |
9 | 77761385441147 |
10 | 20011213422241 |
11 | 6415787316148 |
12 | 22b2382a77081 |
13 | b220844b4b22 |
14 | 4d2795605a6d |
15 | 24a80e531611 |
hex | 123339447ea1 |
20011213422241 has 2 divisors, whose sum is σ = 20011213422242. Its totient is φ = 20011213422240.
The previous prime is 20011213422227. The next prime is 20011213422301. The reversal of 20011213422241 is 14222431211002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14413867833600 + 5597345588641 = 3796560^2 + 2365871^2 .
It is a cyclic number.
It is not a de Polignac number, because 20011213422241 - 29 = 20011213421729 is a prime.
It is not a weakly prime, because it can be changed into another prime (20011213422841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005606711120 + 10005606711121.
It is an arithmetic number, because the mean of its divisors is an integer number (10005606711121).
Almost surely, 220011213422241 is an apocalyptic number.
It is an amenable number.
20011213422241 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011213422241 is an equidigital number, since it uses as much as digits as its factorization.
20011213422241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 20011213422241 its reverse (14222431211002), we get a palindrome (34233644633243).
The spelling of 20011213422241 in words is "twenty trillion, eleven billion, two hundred thirteen million, four hundred twenty-two thousand, two hundred forty-one".
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