Base | Representation |
---|---|
bin | 1011101001011110011… |
… | …1100000011000100001 |
3 | 201010112011102121201111 |
4 | 2322113213200120201 |
5 | 11234312211231424 |
6 | 231532535103321 |
7 | 20312652506131 |
oct | 2722747403041 |
9 | 633464377644 |
10 | 200112211489 |
11 | 7795a143373 |
12 | 32949211b41 |
13 | 15b41649cc8 |
14 | 9984d70ac1 |
15 | 531323c194 |
hex | 2e979e0621 |
200112211489 has 2 divisors, whose sum is σ = 200112211490. Its totient is φ = 200112211488.
The previous prime is 200112211447. The next prime is 200112211493. The reversal of 200112211489 is 984112211002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 154244707600 + 45867503889 = 392740^2 + 214167^2 .
It is a cyclic number.
It is not a de Polignac number, because 200112211489 - 217 = 200112080417 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 200112211489.
It is not a weakly prime, because it can be changed into another prime (200112215489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056105744 + 100056105745.
It is an arithmetic number, because the mean of its divisors is an integer number (100056105745).
Almost surely, 2200112211489 is an apocalyptic number.
It is an amenable number.
200112211489 is a deficient number, since it is larger than the sum of its proper divisors (1).
200112211489 is an equidigital number, since it uses as much as digits as its factorization.
200112211489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 31.
The spelling of 200112211489 in words is "two hundred billion, one hundred twelve million, two hundred eleven thousand, four hundred eighty-nine".
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