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200113121221003 is a prime number
BaseRepresentation
bin101101100000000001110111…
…100000010101100110001011
3222020112121221111011111020101
4231200001313200111212023
5202212123133013033003
61545334410533510231
760102460456655614
oct5540016740254613
9866477844144211
10200113121221003
1158842552a99a51
121a53b31b4a2377
138787781303c03
14375b753566c0b
1518206051c311d
hexb6007781598b

200113121221003 has 2 divisors, whose sum is σ = 200113121221004. Its totient is φ = 200113121221002.

The previous prime is 200113121220997. The next prime is 200113121221007. The reversal of 200113121221003 is 300122121311002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200113121221003 is a prime.

It is a super-2 number, since 2×2001131212210032 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (200113121221007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100056560610501 + 100056560610502.

It is an arithmetic number, because the mean of its divisors is an integer number (100056560610502).

Almost surely, 2200113121221003 is an apocalyptic number.

200113121221003 is a deficient number, since it is larger than the sum of its proper divisors (1).

200113121221003 is an equidigital number, since it uses as much as digits as its factorization.

200113121221003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 200113121221003 its reverse (300122121311002), we get a palindrome (500235242532005).

The spelling of 200113121221003 in words is "two hundred trillion, one hundred thirteen billion, one hundred twenty-one million, two hundred twenty-one thousand, three".