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20011334442 = 23111492034913
BaseRepresentation
bin10010101000110001…
…001011101100101010
31220122121212010011220
4102220301023230222
5311440400200232
613105412202510
71305620351631
oct225061135452
956577763156
1020011334442
118539970830
123a65909436
131b6bb459c8
14d7b9d6518
157c1c5942c
hex4a8c4bb2a

20011334442 has 32 divisors (see below), whose sum is σ = 43954142400. Its totient is φ = 6023339520.

The previous prime is 20011334417. The next prime is 20011334461. The reversal of 20011334442 is 24443311002.

It is a super-2 number, since 2×200113344422 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1007623 + ... + 1027290.

It is an arithmetic number, because the mean of its divisors is an integer number (1373566950).

Almost surely, 220011334442 is an apocalyptic number.

20011334442 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

20011334442 is an abundant number, since it is smaller than the sum of its proper divisors (23942807958).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20011334442 is a wasteful number, since it uses less digits than its factorization.

20011334442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2035078.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 20011334442 its reverse (24443311002), we get a palindrome (44454645444).

It can be divided in two parts, 20011 and 334442, that added together give a palindrome (354453).

The spelling of 20011334442 in words is "twenty billion, eleven million, three hundred thirty-four thousand, four hundred forty-two".

Divisors: 1 2 3 6 11 22 33 66 149 298 447 894 1639 3278 4917 9834 2034913 4069826 6104739 12209478 22384043 44768086 67152129 134304258 303202037 606404074 909606111 1819212222 3335222407 6670444814 10005667221 20011334442