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200113411233 = 366704470411
BaseRepresentation
bin1011101001011110110…
…0000101010010100001
3201010112020200120110110
42322113230011102201
511234313013124413
6231533020521533
720312665634001
oct2722754052241
9633466616413
10200113411233
117795a89279a
12329496b02a9
1315b4197a108
1499851a4001
1553133c78c3
hex2e97b054a1

200113411233 has 4 divisors (see below), whose sum is σ = 266817881648. Its totient is φ = 133408940820.

The previous prime is 200113411189. The next prime is 200113411291. The reversal of 200113411233 is 332114311002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 200113411233 - 213 = 200113403041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200113911233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33352235203 + ... + 33352235208.

It is an arithmetic number, because the mean of its divisors is an integer number (66704470412).

Almost surely, 2200113411233 is an apocalyptic number.

It is an amenable number.

200113411233 is a deficient number, since it is larger than the sum of its proper divisors (66704470415).

200113411233 is an equidigital number, since it uses as much as digits as its factorization.

200113411233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66704470414.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 200113411233 its reverse (332114311002), we get a palindrome (532227722235).

The spelling of 200113411233 in words is "two hundred billion, one hundred thirteen million, four hundred eleven thousand, two hundred thirty-three".

Divisors: 1 3 66704470411 200113411233