Base | Representation |
---|---|
bin | 1011101001100000010… |
… | …1101011011110000001 |
3 | 201010112201022110211101 |
4 | 2322120011223132001 |
5 | 11234321222334332 |
6 | 231533420414401 |
7 | 20313106651432 |
oct | 2723005533601 |
9 | 633481273741 |
10 | 200120121217 |
11 | 77963656035 |
12 | 3294b9a7401 |
13 | 15b43189313 |
14 | 998602d489 |
15 | 5313ca0ae7 |
hex | 2e9816b781 |
200120121217 has 2 divisors, whose sum is σ = 200120121218. Its totient is φ = 200120121216.
The previous prime is 200120121209. The next prime is 200120121269. The reversal of 200120121217 is 712121021002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 198919568016 + 1200553201 = 446004^2 + 34649^2 .
It is a cyclic number.
It is not a de Polignac number, because 200120121217 - 23 = 200120121209 is a prime.
It is a super-2 number, since 2×2001201212172 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 200120121194 and 200120121203.
It is not a weakly prime, because it can be changed into another prime (200120121277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100060060608 + 100060060609.
It is an arithmetic number, because the mean of its divisors is an integer number (100060060609).
Almost surely, 2200120121217 is an apocalyptic number.
It is an amenable number.
200120121217 is a deficient number, since it is larger than the sum of its proper divisors (1).
200120121217 is an equidigital number, since it uses as much as digits as its factorization.
200120121217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 200120121217 its reverse (712121021002), we get a palindrome (912241142219).
The spelling of 200120121217 in words is "two hundred billion, one hundred twenty million, one hundred twenty-one thousand, two hundred seventeen".
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