Base | Representation |
---|---|
bin | 11101000111110000111… |
… | …100100110100011000110 |
3 | 21002022110020000111102221 |
4 | 131013300330212203012 |
5 | 230241430231223024 |
6 | 4131201204322554 |
7 | 264403441062316 |
oct | 35076074464306 |
9 | 7068406014387 |
10 | 2001202211014 |
11 | 701783527806 |
12 | 283a1a6a345a |
13 | 116935651036 |
14 | 6cc043d7446 |
15 | 370c88033e4 |
hex | 1d1f0f268c6 |
2001202211014 has 64 divisors (see below), whose sum is σ = 3134012290560. Its totient is φ = 957900867840.
The previous prime is 2001202210981. The next prime is 2001202211053. The reversal of 2001202211014 is 4101122021002.
It is a super-4 number, since 4×20012022110144 (a number of 50 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 180787872 + ... + 180798940.
It is an arithmetic number, because the mean of its divisors is an integer number (48968942040).
Almost surely, 22001202211014 is an apocalyptic number.
2001202211014 is a deficient number, since it is larger than the sum of its proper divisors (1132810079546).
2001202211014 is a wasteful number, since it uses less digits than its factorization.
2001202211014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11485.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 2001202211014 its reverse (4101122021002), we get a palindrome (6102324232016).
The spelling of 2001202211014 in words is "two trillion, one billion, two hundred two million, two hundred eleven thousand, fourteen".
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