Base | Representation |
---|---|
bin | 11101000111110001011… |
… | …110100101101000110001 |
3 | 21002022110211210010111221 |
4 | 131013301132211220301 |
5 | 230241440021321202 |
6 | 4131202123305041 |
7 | 264403606566463 |
oct | 35076136455061 |
9 | 7068424703457 |
10 | 2001211120177 |
11 | 701788562355 |
12 | 283a2167b181 |
13 | 116937450229 |
14 | 6cc05676133 |
15 | 370c94b3037 |
hex | 1d1f17a5a31 |
2001211120177 has 2 divisors, whose sum is σ = 2001211120178. Its totient is φ = 2001211120176.
The previous prime is 2001211120109. The next prime is 2001211120211. The reversal of 2001211120177 is 7710211121002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1843848957456 + 157362162721 = 1357884^2 + 396689^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001211120177 - 27 = 2001211120049 is a prime.
It is a super-2 number, since 2×20012111201772 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2001211120277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000605560088 + 1000605560089.
It is an arithmetic number, because the mean of its divisors is an integer number (1000605560089).
Almost surely, 22001211120177 is an apocalyptic number.
It is an amenable number.
2001211120177 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001211120177 is an equidigital number, since it uses as much as digits as its factorization.
2001211120177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 392, while the sum is 25.
Adding to 2001211120177 its reverse (7710211121002), we get a palindrome (9711422241179).
The spelling of 2001211120177 in words is "two trillion, one billion, two hundred eleven million, one hundred twenty thousand, one hundred seventy-seven".
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