Base | Representation |
---|---|
bin | 11101000111110001100… |
… | …001111111101101111001 |
3 | 21002022110220110111211111 |
4 | 131013301201333231321 |
5 | 230241440233412213 |
6 | 4131202154400321 |
7 | 264403620306643 |
oct | 35076141775571 |
9 | 7068426414744 |
10 | 2001212013433 |
11 | 701789012486 |
12 | 283a21a300a1 |
13 | 1169376a3999 |
14 | 6cc05829893 |
15 | 370c95dca3d |
hex | 1d1f187fb79 |
2001212013433 has 2 divisors, whose sum is σ = 2001212013434. Its totient is φ = 2001212013432.
The previous prime is 2001212013421. The next prime is 2001212013457. The reversal of 2001212013433 is 3343102121002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1847133782649 + 154078230784 = 1359093^2 + 392528^2 .
It is a cyclic number.
It is not a de Polignac number, because 2001212013433 - 217 = 2001211882361 is a prime.
It is not a weakly prime, because it can be changed into another prime (2001212013133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000606006716 + 1000606006717.
It is an arithmetic number, because the mean of its divisors is an integer number (1000606006717).
Almost surely, 22001212013433 is an apocalyptic number.
It is an amenable number.
2001212013433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001212013433 is an equidigital number, since it uses as much as digits as its factorization.
2001212013433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 2001212013433 its reverse (3343102121002), we get a palindrome (5344314134435).
The spelling of 2001212013433 in words is "two trillion, one billion, two hundred twelve million, thirteen thousand, four hundred thirty-three".
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