Base | Representation |
---|---|
bin | 11101000111110010000… |
… | …000110110010001100001 |
3 | 21002022111110200102012001 |
4 | 131013302000312101201 |
5 | 230241444321214332 |
6 | 4131203044004001 |
7 | 264404046123331 |
oct | 35076200662141 |
9 | 7068443612161 |
10 | 2001220101217 |
11 | 7017926369a7 |
12 | 283a24690601 |
13 | 11693927605c |
14 | 6cc069330c1 |
15 | 370ca1890e7 |
hex | 1d1f2036461 |
2001220101217 has 2 divisors, whose sum is σ = 2001220101218. Its totient is φ = 2001220101216.
The previous prime is 2001220101151. The next prime is 2001220101233. The reversal of 2001220101217 is 7121010221002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1097977048336 + 903243052881 = 1047844^2 + 950391^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2001220101217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2001220101194 and 2001220101203.
It is not a weakly prime, because it can be changed into another prime (2001220104217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000610050608 + 1000610050609.
It is an arithmetic number, because the mean of its divisors is an integer number (1000610050609).
Almost surely, 22001220101217 is an apocalyptic number.
It is an amenable number.
2001220101217 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001220101217 is an equidigital number, since it uses as much as digits as its factorization.
2001220101217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 2001220101217 its reverse (7121010221002), we get a palindrome (9122230322219).
The spelling of 2001220101217 in words is "two trillion, one billion, two hundred twenty million, one hundred one thousand, two hundred seventeen".
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