Base | Representation |
---|---|
bin | 1001000110011011101001… |
… | …10011001101000110100011 |
3 | 2121212011000110220011022202 |
4 | 10203031310303031012203 |
5 | 10110340002311242011 |
6 | 110321252224123415 |
7 | 4133556163064606 |
oct | 443156463150643 |
9 | 77764013804282 |
10 | 20012212212131 |
11 | 641614a092837 |
12 | 22b260146656b |
13 | b221b33ba269 |
14 | 4d284c11a33d |
15 | 24a86c07423b |
hex | 123374ccd1a3 |
20012212212131 has 2 divisors, whose sum is σ = 20012212212132. Its totient is φ = 20012212212130.
The previous prime is 20012212212073. The next prime is 20012212212149. The reversal of 20012212212131 is 13121221221002.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20012212212131 is a prime.
It is a super-2 number, since 2×200122122121312 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (20012212212431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006106106065 + 10006106106066.
It is an arithmetic number, because the mean of its divisors is an integer number (10006106106066).
Almost surely, 220012212212131 is an apocalyptic number.
20012212212131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20012212212131 is an equidigital number, since it uses as much as digits as its factorization.
20012212212131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 20012212212131 its reverse (13121221221002), we get a palindrome (33133433433133).
The spelling of 20012212212131 in words is "twenty trillion, twelve billion, two hundred twelve million, two hundred twelve thousand, one hundred thirty-one".
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