Base | Representation |
---|---|
bin | 11101000111110010101… |
… | …011001100101100101001 |
3 | 21002022112020120110010101 |
4 | 131013302223030230221 |
5 | 230242010141444423 |
6 | 4131204121545401 |
7 | 264404242362352 |
oct | 35076253145451 |
9 | 7068466513111 |
10 | 2001231203113 |
11 | 701798929a1a |
12 | 283a28345261 |
13 | 11693b66231c |
14 | 6cc081c2d29 |
15 | 370cb12d7ad |
hex | 1d1f2accb29 |
2001231203113 has 4 divisors (see below), whose sum is σ = 2001293674128. Its totient is φ = 2001168732100.
The previous prime is 2001231203057. The next prime is 2001231203173. The reversal of 2001231203113 is 3113021321002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2001231203113 - 233 = 1992641268521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2001231203173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31187431 + ... + 31251532.
It is an arithmetic number, because the mean of its divisors is an integer number (500323418532).
Almost surely, 22001231203113 is an apocalyptic number.
It is an amenable number.
2001231203113 is a deficient number, since it is larger than the sum of its proper divisors (62471015).
2001231203113 is an equidigital number, since it uses as much as digits as its factorization.
2001231203113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62471014.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2001231203113 its reverse (3113021321002), we get a palindrome (5114252524115).
The spelling of 2001231203113 in words is "two trillion, one billion, two hundred thirty-one million, two hundred three thousand, one hundred thirteen".
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