Base | Representation |
---|---|
bin | 101101100000010000110001… |
… | …011010101111110111101011 |
3 | 222020121011020211111212101021 |
4 | 231200100301122233313223 |
5 | 202212403422024013234 |
6 | 1545350014555033311 |
7 | 60103565200502365 |
oct | 5540206132576753 |
9 | 866534224455337 |
10 | 200129125219819 |
11 | 58849315916154 |
12 | 1a54244713b837 |
13 | 8789131b5a2b3 |
14 | 375c430c59d35 |
15 | 1820c402089b4 |
hex | b604316afdeb |
200129125219819 has 2 divisors, whose sum is σ = 200129125219820. Its totient is φ = 200129125219818.
The previous prime is 200129125219753. The next prime is 200129125219921. The reversal of 200129125219819 is 918912521921002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200129125219819 - 219 = 200129124695531 is a prime.
It is a super-2 number, since 2×2001291252198192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200129125019819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100064562609909 + 100064562609910.
It is an arithmetic number, because the mean of its divisors is an integer number (100064562609910).
Almost surely, 2200129125219819 is an apocalyptic number.
200129125219819 is a deficient number, since it is larger than the sum of its proper divisors (1).
200129125219819 is an equidigital number, since it uses as much as digits as its factorization.
200129125219819 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 52.
The spelling of 200129125219819 in words is "two hundred trillion, one hundred twenty-nine billion, one hundred twenty-five million, two hundred nineteen thousand, eight hundred nineteen".
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