Base | Representation |
---|---|
bin | 1001000110011101001110… |
… | …00110001010110110100011 |
3 | 2121212020012021201021122122 |
4 | 10203032213012022312203 |
5 | 10110343214321410301 |
6 | 110321512050254455 |
7 | 4133616120410261 |
oct | 443164706126643 |
9 | 77766167637578 |
10 | 20013056044451 |
11 | 6416542441518 |
12 | 22b27b7b8742b |
13 | b222b9179122 |
14 | 4d28cc215431 |
15 | 24a8bb1a881b |
hex | 1233a718ada3 |
20013056044451 has 2 divisors, whose sum is σ = 20013056044452. Its totient is φ = 20013056044450.
The previous prime is 20013056044427. The next prime is 20013056044489. The reversal of 20013056044451 is 15444065031002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20013056044451 - 222 = 20013051850147 is a prime.
It is not a weakly prime, because it can be changed into another prime (20013056044951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10006528022225 + 10006528022226.
It is an arithmetic number, because the mean of its divisors is an integer number (10006528022226).
Almost surely, 220013056044451 is an apocalyptic number.
20013056044451 is a deficient number, since it is larger than the sum of its proper divisors (1).
20013056044451 is an equidigital number, since it uses as much as digits as its factorization.
20013056044451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
The spelling of 20013056044451 in words is "twenty trillion, thirteen billion, fifty-six million, forty-four thousand, four hundred fifty-one".
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