Base | Representation |
---|---|
bin | 11101000111111000100… |
… | …100000111110010110010 |
3 | 21002022210010111102111101 |
4 | 131013320210013302302 |
5 | 230242210440330224 |
6 | 4131222011435014 |
7 | 264406552262044 |
oct | 35077044076262 |
9 | 7068703442441 |
10 | 2001330011314 |
11 | 701839686a97 |
12 | 283a55455a6a |
13 | 116955c7950a |
14 | 6cc17383a94 |
15 | 370d4b4a044 |
hex | 1d1f8907cb2 |
2001330011314 has 32 divisors (see below), whose sum is σ = 3142788030720. Its totient is φ = 954021100032.
The previous prime is 2001330011309. The next prime is 2001330011333. The reversal of 2001330011314 is 4131100331002.
It is a junction number, because it is equal to n+sod(n) for n = 2001330011291 and 2001330011300.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54688267 + ... + 54724849.
It is an arithmetic number, because the mean of its divisors is an integer number (98212125960).
Almost surely, 22001330011314 is an apocalyptic number.
2001330011314 is a deficient number, since it is larger than the sum of its proper divisors (1141458019406).
2001330011314 is a wasteful number, since it uses less digits than its factorization.
2001330011314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40474.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2001330011314 its reverse (4131100331002), we get a palindrome (6132430342316).
The spelling of 2001330011314 in words is "two trillion, one billion, three hundred thirty million, eleven thousand, three hundred fourteen".
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