Base | Representation |
---|---|
bin | 101101100000010100100100… |
… | …011110101011010010011001 |
3 | 222020121112210000210022100020 |
4 | 231200110210132223102121 |
5 | 202212440244444104423 |
6 | 1545351531350301053 |
7 | 60104101225146204 |
oct | 5540244436532231 |
9 | 866545700708306 |
10 | 200133203113113 |
11 | 588500187717a6 |
12 | 1a5431a4957789 |
13 | 87896319521ca |
14 | 375c6da68893b |
15 | 1820dcd2184e3 |
hex | b605247ab499 |
200133203113113 has 8 divisors (see below), whose sum is σ = 267793894558176. Its totient is φ = 132947323538400.
The previous prime is 200133203113073. The next prime is 200133203113127. The reversal of 200133203113113 is 311311302331002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 200133203113113 - 26 = 200133203113049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200133201113113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118702966603 + ... + 118702968288.
It is an arithmetic number, because the mean of its divisors is an integer number (33474236819772).
Almost surely, 2200133203113113 is an apocalyptic number.
It is an amenable number.
200133203113113 is a deficient number, since it is larger than the sum of its proper divisors (67660691445063).
200133203113113 is a wasteful number, since it uses less digits than its factorization.
200133203113113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237405935175.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 200133203113113 its reverse (311311302331002), we get a palindrome (511444505444115).
The spelling of 200133203113113 in words is "two hundred trillion, one hundred thirty-three billion, two hundred three million, one hundred thirteen thousand, one hundred thirteen".
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