Base | Representation |
---|---|
bin | 10111110110111… |
… | …00111101010011 |
3 | 111221120212220021 |
4 | 23323130331103 |
5 | 402213300413 |
6 | 31505324311 |
7 | 4650054313 |
oct | 1373347523 |
9 | 457525807 |
10 | 200134483 |
11 | a2a74aaa |
12 | 57036697 |
13 | 32603593 |
14 | 1c819443 |
15 | 1288418d |
hex | bedcf53 |
200134483 has 2 divisors, whose sum is σ = 200134484. Its totient is φ = 200134482.
The previous prime is 200134469. The next prime is 200134547. The reversal of 200134483 is 384431002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200134483 - 213 = 200126291 is a prime.
It is a super-2 number, since 2×2001344832 = 80107622571354578, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (200134283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100067241 + 100067242.
It is an arithmetic number, because the mean of its divisors is an integer number (100067242).
Almost surely, 2200134483 is an apocalyptic number.
200134483 is a deficient number, since it is larger than the sum of its proper divisors (1).
200134483 is an equidigital number, since it uses as much as digits as its factorization.
200134483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
The square root of 200134483 is about 14146.8895167807. The cubic root of 200134483 is about 584.9345951667.
Adding to 200134483 its reverse (384431002), we get a palindrome (584565485).
The spelling of 200134483 in words is "two hundred million, one hundred thirty-four thousand, four hundred eighty-three".
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