Base | Representation |
---|---|
bin | 1001000110011110010110… |
… | …10101011000101011001001 |
3 | 2121212021202122201021201100 |
4 | 10203033023111120223021 |
5 | 10110400440441404001 |
6 | 110322052245212013 |
7 | 4133640152145321 |
oct | 443171325305311 |
9 | 77767678637640 |
10 | 20013664013001 |
11 | 641682464226a |
12 | 22b2947701009 |
13 | b22385104a29 |
14 | 4d2948c74281 |
15 | 24a90474c586 |
hex | 1233cb558ac9 |
20013664013001 has 6 divisors (see below), whose sum is σ = 28908625796570. Its totient is φ = 13342442675328.
The previous prime is 20013664012967. The next prime is 20013664013011. The reversal of 20013664013001 is 10031046631002.
20013664013001 is a `hidden beast` number, since 2 + 0 + 0 + 1 + 3 + 6 + 640 + 13 + 0 + 0 + 1 = 666.
It can be written as a sum of positive squares in only one way, i.e., 19868628715776 + 145035297225 = 4457424^2 + 380835^2 .
It is not a de Polignac number, because 20013664013001 - 211 = 20013664010953 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20013664013011) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1111870222936 + ... + 1111870222953.
Almost surely, 220013664013001 is an apocalyptic number.
It is an amenable number.
20013664013001 is a deficient number, since it is larger than the sum of its proper divisors (8894961783569).
20013664013001 is a wasteful number, since it uses less digits than its factorization.
20013664013001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2223740445895 (or 2223740445892 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
The spelling of 20013664013001 in words is "twenty trillion, thirteen billion, six hundred sixty-four million, thirteen thousand, one".
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