Base | Representation |
---|---|
bin | 1001000110011110011101… |
… | …01111110001000001110011 |
3 | 2121212021220122102202001000 |
4 | 10203033032233301001303 |
5 | 10110401100120311042 |
6 | 110322102052213043 |
7 | 4133641445555526 |
oct | 443171657610163 |
9 | 77767818382030 |
10 | 20013721260147 |
11 | 641685399295a |
12 | 22b296290a183 |
13 | b22393c29994 |
14 | 4d29526d6bbd |
15 | 24a9097a974c |
hex | 1233cebf1073 |
20013721260147 has 32 divisors (see below), whose sum is σ = 30015671938560. Its totient is φ = 13178000233440.
The previous prime is 20013721260131. The next prime is 20013721260173. The reversal of 20013721260147 is 74106212731002.
20013721260147 is a `hidden beast` number, since 2 + 0 + 0 + 1 + 3 + 7 + 2 + 1 + 2 + 601 + 47 = 666.
It is not a de Polignac number, because 20013721260147 - 24 = 20013721260131 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20013721260187) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6674338 + ... + 9196424.
It is an arithmetic number, because the mean of its divisors is an integer number (937989748080).
Almost surely, 220013721260147 is an apocalyptic number.
20013721260147 is a gapful number since it is divisible by the number (27) formed by its first and last digit.
20013721260147 is a deficient number, since it is larger than the sum of its proper divisors (10001950678413).
20013721260147 is a wasteful number, since it uses less digits than its factorization.
20013721260147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2525720 (or 2525714 counting only the distinct ones).
The product of its (nonzero) digits is 28224, while the sum is 36.
Adding to 20013721260147 its reverse (74106212731002), we get a palindrome (94119933991149).
The spelling of 20013721260147 in words is "twenty trillion, thirteen billion, seven hundred twenty-one million, two hundred sixty thousand, one hundred forty-seven".
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