Base | Representation |
---|---|
bin | 101101100000011011111101… |
… | …011000100001111110011011 |
3 | 222020122022020222000212221112 |
4 | 231200123331120201332123 |
5 | 202213103022101002100 |
6 | 1545355322531530535 |
7 | 60104501645143043 |
oct | 5540337530417633 |
9 | 866568228025845 |
10 | 200141137125275 |
11 | 5885341a269545 |
12 | 1a544839a59a4b |
13 | 878a2c75cca68 |
14 | 375cc50296723 |
15 | 18211e4a2bb35 |
hex | b606fd621f9b |
200141137125275 has 48 divisors (see below), whose sum is σ = 270973940307840. Its totient is φ = 146128767724800.
The previous prime is 200141137125239. The next prime is 200141137125287. The reversal of 200141137125275 is 572521731141002.
It is not a de Polignac number, because 200141137125275 - 222 = 200141132930971 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 65624261 + ... + 68606310.
It is an arithmetic number, because the mean of its divisors is an integer number (5645290423080).
Almost surely, 2200141137125275 is an apocalyptic number.
200141137125275 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
200141137125275 is a deficient number, since it is larger than the sum of its proper divisors (70832803182565).
200141137125275 is a wasteful number, since it uses less digits than its factorization.
200141137125275 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 134230716 (or 134230711 counting only the distinct ones).
The product of its (nonzero) digits is 117600, while the sum is 41.
Adding to 200141137125275 its reverse (572521731141002), we get a palindrome (772662868266277).
The spelling of 200141137125275 in words is "two hundred trillion, one hundred forty-one billion, one hundred thirty-seven million, one hundred twenty-five thousand, two hundred seventy-five".
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