Search a number
-
+
20014120131 = 39133730469
BaseRepresentation
bin10010101000111011…
…110011110011000011
31220122211002122102120
4102220323303303003
5311442103321011
613105552015323
71305653133315
oct225073636303
956584078376
1020014120131
1185404a3755
123a66831543
131b6c5ac945
14d7c11d7b5
157c2109a06
hex4a8ef3cc3

20014120131 has 8 divisors (see below), whose sum is σ = 26688451920. Its totient is φ = 13341267552.

The previous prime is 20014120123. The next prime is 20014120153. The reversal of 20014120131 is 13102141002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 20014120131 - 23 = 20014120123 is a prime.

It is a super-2 number, since 2×200141201312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 20014120131.

It is not an unprimeable number, because it can be changed into a prime (20014120171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 337836 + ... + 392633.

It is an arithmetic number, because the mean of its divisors is an integer number (3336056490).

Almost surely, 220014120131 is an apocalyptic number.

20014120131 is a deficient number, since it is larger than the sum of its proper divisors (6674331789).

20014120131 is an equidigital number, since it uses as much as digits as its factorization.

20014120131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 739605.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 20014120131 its reverse (13102141002), we get a palindrome (33116261133).

The spelling of 20014120131 in words is "twenty billion, fourteen million, one hundred twenty thousand, one hundred thirty-one".

Divisors: 1 3 9133 27399 730469 2191407 6671373377 20014120131