200141331113 has 4 divisors (see below), whose sum is σ = 200171196288. Its totient is φ = 200111465940.

The previous prime is 200141331107. The next prime is 200141331133. The reversal of 200141331113 is 311133141002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311133141002 = 2 ⋅155566570501.

It is a cyclic number.

It is not a de Polignac number, because 200141331113 - 2¹² = 200141327017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200141331133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14922533 + ... + 14935938.

It is an arithmetic number, because the mean of its divisors is an integer number (50042799072).

Almost surely, 2^200141331113 is an apocalyptic number.

It is an amenable number.

200141331113 is a deficient number, since it is larger than the sum of its proper divisors (29865175).

200141331113 is an equidigital number, since it uses as much as digits as its factorization.

200141331113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29865174.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 200141331113 its reverse (311133141002), we get a palindrome (511274472115).

The spelling of 200141331113 in words is "two hundred billion, one hundred forty-one million, three hundred thirty-one thousand, one hundred thirteen".