Base | Representation |
---|---|
bin | 11101000111111101100… |
… | …001111000111010001111 |
3 | 21002022222221020112202021 |
4 | 131013331201320322033 |
5 | 230242343301442033 |
6 | 4131234145111011 |
7 | 264411613313440 |
oct | 35077541707217 |
9 | 7068887215667 |
10 | 2001413312143 |
11 | 701881702153 |
12 | 283a79328467 |
13 | 11696a2c414b |
14 | 6cc244692c7 |
15 | 370dc101b2d |
hex | 1d1fd878e8f |
2001413312143 has 16 divisors (see below), whose sum is σ = 2297774090304. Its totient is φ = 1707675943680.
The previous prime is 2001413312111. The next prime is 2001413312149. The reversal of 2001413312143 is 3412133141002.
It is not a de Polignac number, because 2001413312143 - 25 = 2001413312111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2001413312149) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1450821 + ... + 2471377.
It is an arithmetic number, because the mean of its divisors is an integer number (143610880644).
Almost surely, 22001413312143 is an apocalyptic number.
2001413312143 is a deficient number, since it is larger than the sum of its proper divisors (296360778161).
2001413312143 is a wasteful number, since it uses less digits than its factorization.
2001413312143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1021842.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 2001413312143 its reverse (3412133141002), we get a palindrome (5413546453145).
The spelling of 2001413312143 in words is "two trillion, one billion, four hundred thirteen million, three hundred twelve thousand, one hundred forty-three".
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