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20014706750593 is a prime number
BaseRepresentation
bin1001000110100000010010…
…11111000111010010000001
32121212101110022210211210011
410203100021133013102001
510110410104412004333
6110322343534504521
74134005043235522
oct443201137072201
977771408724704
1020014706750593
11641720a1a6475
1222b2b98965141
13b224c0156819
144d2a07548849
1524a9660719cd
hex1234097c7481

20014706750593 has 2 divisors, whose sum is σ = 20014706750594. Its totient is φ = 20014706750592.

The previous prime is 20014706750543. The next prime is 20014706750617. The reversal of 20014706750593 is 39505760741002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18276454359409 + 1738252391184 = 4275097^2 + 1318428^2 .

It is a cyclic number.

It is not a de Polignac number, because 20014706750593 - 217 = 20014706619521 is a prime.

It is a super-3 number, since 3×200147067505933 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (20014706750503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10007353375296 + 10007353375297.

It is an arithmetic number, because the mean of its divisors is an integer number (10007353375297).

Almost surely, 220014706750593 is an apocalyptic number.

It is an amenable number.

20014706750593 is a deficient number, since it is larger than the sum of its proper divisors (1).

20014706750593 is an equidigital number, since it uses as much as digits as its factorization.

20014706750593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1587600, while the sum is 49.

The spelling of 20014706750593 in words is "twenty trillion, fourteen billion, seven hundred six million, seven hundred fifty thousand, five hundred ninety-three".