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20014793 is a prime number
BaseRepresentation
bin100110001011…
…0011011001001
31101122212010122
41030112123021
520110433133
61552553025
7332060111
oct114263311
941585118
1020014793
1110330457
126852775
1341ba096
142930041
151b55498
hex13166c9

20014793 has 2 divisors, whose sum is σ = 20014794. Its totient is φ = 20014792.

The previous prime is 20014789. The next prime is 20014811. The reversal of 20014793 is 39741002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16581184 + 3433609 = 4072^2 + 1853^2 .

It is a cyclic number.

It is not a de Polignac number, because 20014793 - 22 = 20014789 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20014493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10007396 + 10007397.

It is an arithmetic number, because the mean of its divisors is an integer number (10007397).

Almost surely, 220014793 is an apocalyptic number.

It is an amenable number.

20014793 is a deficient number, since it is larger than the sum of its proper divisors (1).

20014793 is an equidigital number, since it uses as much as digits as its factorization.

20014793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 26.

The square root of 20014793 is about 4473.7895569640. The cubic root of 20014793 is about 271.5086691325.

Adding to 20014793 its reverse (39741002), we get a palindrome (59755795).

The spelling of 20014793 in words is "twenty million, fourteen thousand, seven hundred ninety-three".