Base | Representation |
---|---|
bin | 101101100001011100010001… |
… | …111110001010100101010011 |
3 | 222020212220112012210122112122 |
4 | 231201130101332022211103 |
5 | 202220220443203340422 |
6 | 1545451144100044455 |
7 | 60112465306040636 |
oct | 5541342176124523 |
9 | 866786465718478 |
10 | 200210202011987 |
11 | 5887a740626112 |
12 | 1a5560b369372b |
13 | 87939830a852b |
14 | 3762322a11c1d |
15 | 1822dd7ec6d42 |
hex | b61711f8a953 |
200210202011987 has 2 divisors, whose sum is σ = 200210202011988. Its totient is φ = 200210202011986.
The previous prime is 200210202011977. The next prime is 200210202012103. The reversal of 200210202011987 is 789110202012002.
200210202011987 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200210202011987 - 212 = 200210202007891 is a prime.
It is not a weakly prime, because it can be changed into another prime (200210202011957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105101005993 + 100105101005994.
It is an arithmetic number, because the mean of its divisors is an integer number (100105101005994).
Almost surely, 2200210202011987 is an apocalyptic number.
200210202011987 is a deficient number, since it is larger than the sum of its proper divisors (1).
200210202011987 is an equidigital number, since it uses as much as digits as its factorization.
200210202011987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 35.
Adding to 200210202011987 its reverse (789110202012002), we get a palindrome (989320404023989).
The spelling of 200210202011987 in words is "two hundred trillion, two hundred ten billion, two hundred two million, eleven thousand, nine hundred eighty-seven".
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