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2002110010993 = 3164584193903
BaseRepresentation
bin11101001000100111000…
…011100101011001110001
321002101210111012111220101
4131020213003211121301
5230300310130322433
64131431233512401
7264435103205431
oct35104703453161
97071714174811
102002110010993
117020a99a7324
12284032712701
13116a4b748aa1
146cc8cbc42c1
153712d37107d
hex1d2270e5671

2002110010993 has 4 divisors (see below), whose sum is σ = 2066694204928. Its totient is φ = 1937525817060.

The previous prime is 2002110010969. The next prime is 2002110011003. The reversal of 2002110010993 is 3990100112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002110010993 - 25 = 2002110010961 is a prime.

It is a super-2 number, since 2×20021100109932 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002110010193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32292096921 + ... + 32292096982.

It is an arithmetic number, because the mean of its divisors is an integer number (516673551232).

Almost surely, 22002110010993 is an apocalyptic number.

It is an amenable number.

2002110010993 is a deficient number, since it is larger than the sum of its proper divisors (64584193935).

2002110010993 is an equidigital number, since it uses as much as digits as its factorization.

2002110010993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64584193934.

The product of its (nonzero) digits is 972, while the sum is 28.

Adding to 2002110010993 its reverse (3990100112002), we get a palindrome (5992210122995).

The spelling of 2002110010993 in words is "two trillion, two billion, one hundred ten million, ten thousand, nine hundred ninety-three".

Divisors: 1 31 64584193903 2002110010993