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2002111021011 = 3809771824147
BaseRepresentation
bin11101001000100111000…
…111011011111111010011
321002101210120002211101110
4131020213013123333103
5230300310410133021
64131431311304403
7264435114613203
oct35104707337723
97071716084343
102002111021011
117020aa527152
12284032b1b103
13116a4ba1072a
146cc8cda8403
153712d4c0476
hex1d2271dbfd3

2002111021011 has 8 divisors (see below), whose sum is σ = 2669487897024. Its totient is φ = 1334737412840.

The previous prime is 2002111021007. The next prime is 2002111021013. The reversal of 2002111021011 is 1101201112002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2002111021011 - 22 = 2002111021007 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2002111021013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2017240 + ... + 2841386.

It is an arithmetic number, because the mean of its divisors is an integer number (333685987128).

Almost surely, 22002111021011 is an apocalyptic number.

2002111021011 is a deficient number, since it is larger than the sum of its proper divisors (667376876013).

2002111021011 is an equidigital number, since it uses as much as digits as its factorization.

2002111021011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1633921.

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 2002111021011 its reverse (1101201112002), we get a palindrome (3103312133013).

Subtracting from 2002111021011 its reverse (1101201112002), we obtain a palindrome (900909909009).

The spelling of 2002111021011 in words is "two trillion, two billion, one hundred eleven million, twenty-one thousand, eleven".

Divisors: 1 3 809771 824147 2429313 2472441 667370340337 2002111021011