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2002111111993 is a prime number
BaseRepresentation
bin11101001000100111000…
…111110010001100111001
321002101210120021110012011
4131020213013302030321
5230300310421040433
64131431313245521
7264435115442356
oct35104707621471
97071716243164
102002111111993
117020aa589543
12284032b638a1
13116a4ba42c75
146cc8cdcd62d
153712d4dc3cd
hex1d2271f2339

2002111111993 has 2 divisors, whose sum is σ = 2002111111994. Its totient is φ = 2002111111992.

The previous prime is 2002111111967. The next prime is 2002111112081. The reversal of 2002111111993 is 3991111112002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1112037739024 + 890073372969 = 1054532^2 + 943437^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2002111111993 is a prime.

It is not a weakly prime, because it can be changed into another prime (2002111111933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001055555996 + 1001055555997.

It is an arithmetic number, because the mean of its divisors is an integer number (1001055555997).

Almost surely, 22002111111993 is an apocalyptic number.

It is an amenable number.

2002111111993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002111111993 is an equidigital number, since it uses as much as digits as its factorization.

2002111111993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 31.

Adding to 2002111111993 its reverse (3991111112002), we get a palindrome (5993222223995).

The spelling of 2002111111993 in words is "two trillion, two billion, one hundred eleven million, one hundred eleven thousand, nine hundred ninety-three".