Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …100010100110011101001 |
3 | 21002101210122111221000002 |
4 | 131020213030110303221 |
5 | 230300311222133223 |
6 | 4131431354552345 |
7 | 264435131530604 |
oct | 35104714246351 |
9 | 7071718457002 |
10 | 2002112302313 |
11 | 702100221882 |
12 | 2840334386b5 |
13 | 116a4c06b9b6 |
14 | 6cc8d21d33b |
15 | 3712d674e28 |
hex | 1d227314ce9 |
2002112302313 has 4 divisors (see below), whose sum is σ = 2003462345808. Its totient is φ = 2000762258820.
The previous prime is 2002112302273. The next prime is 2002112302343. The reversal of 2002112302313 is 3132032112002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2002112302313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2002112302343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 675019523 + ... + 675022488.
It is an arithmetic number, because the mean of its divisors is an integer number (500865586452).
Almost surely, 22002112302313 is an apocalyptic number.
It is an amenable number.
2002112302313 is a deficient number, since it is larger than the sum of its proper divisors (1350043495).
2002112302313 is a wasteful number, since it uses less digits than its factorization.
2002112302313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1350043494.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2002112302313 its reverse (3132032112002), we get a palindrome (5134144414315).
The spelling of 2002112302313 in words is "two trillion, two billion, one hundred twelve million, three hundred two thousand, three hundred thirteen".
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