Base | Representation |
---|---|
bin | 1001000110101100010000… |
… | …10111011001011010011001 |
3 | 2121220000001000001010011020 |
4 | 10203112020113121122121 |
5 | 10111011233340321213 |
6 | 110325325203553053 |
7 | 4134323163331530 |
oct | 443261027313231 |
9 | 77800030033136 |
10 | 20021130401433 |
11 | 6419a06186417 |
12 | 22b429008b789 |
13 | b22ca4c24c55 |
14 | 4d3056717317 |
15 | 24abdee90923 |
hex | 1235885d9699 |
20021130401433 has 16 divisors (see below), whose sum is σ = 30508535608320. Its totient is φ = 11440591034256.
The previous prime is 20021130401423. The next prime is 20021130401449. The reversal of 20021130401433 is 33410403112002.
It is a happy number.
It is not a de Polignac number, because 20021130401433 - 25 = 20021130401401 is a prime.
It is a super-3 number, since 3×200211304014333 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (20021130401423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2416716 + ... + 6773682.
It is an arithmetic number, because the mean of its divisors is an integer number (1906783475520).
Almost surely, 220021130401433 is an apocalyptic number.
It is an amenable number.
20021130401433 is a deficient number, since it is larger than the sum of its proper divisors (10487405206887).
20021130401433 is a wasteful number, since it uses less digits than its factorization.
20021130401433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4575796.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 20021130401433 its reverse (33410403112002), we get a palindrome (53431533513435).
The spelling of 20021130401433 in words is "twenty trillion, twenty-one billion, one hundred thirty million, four hundred one thousand, four hundred thirty-three".
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