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20021130401433 = 372188194356967
BaseRepresentation
bin1001000110101100010000…
…10111011001011010011001
32121220000001000001010011020
410203112020113121122121
510111011233340321213
6110325325203553053
74134323163331530
oct443261027313231
977800030033136
1020021130401433
116419a06186417
1222b429008b789
13b22ca4c24c55
144d3056717317
1524abdee90923
hex1235885d9699

20021130401433 has 16 divisors (see below), whose sum is σ = 30508535608320. Its totient is φ = 11440591034256.

The previous prime is 20021130401423. The next prime is 20021130401449. The reversal of 20021130401433 is 33410403112002.

It is a happy number.

It is not a de Polignac number, because 20021130401433 - 25 = 20021130401401 is a prime.

It is a super-3 number, since 3×200211304014333 (a number of 41 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (20021130401423) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2416716 + ... + 6773682.

It is an arithmetic number, because the mean of its divisors is an integer number (1906783475520).

Almost surely, 220021130401433 is an apocalyptic number.

It is an amenable number.

20021130401433 is a deficient number, since it is larger than the sum of its proper divisors (10487405206887).

20021130401433 is a wasteful number, since it uses less digits than its factorization.

20021130401433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4575796.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 20021130401433 its reverse (33410403112002), we get a palindrome (53431533513435).

The spelling of 20021130401433 in words is "twenty trillion, twenty-one billion, one hundred thirty million, four hundred one thousand, four hundred thirty-three".

Divisors: 1 3 7 21 218819 656457 1531733 4356967 4595199 13070901 30498769 91496307 953387161973 2860161485919 6673710133811 20021130401433