Base | Representation |
---|---|
bin | 1011101001110110000… |
… | …1100010110111111001 |
3 | 201010210001220110020021 |
4 | 2322131201202313321 |
5 | 11240013043441441 |
6 | 231550435130441 |
7 | 20315265034222 |
oct | 2723541426771 |
9 | 633701813207 |
10 | 200211312121 |
11 | 77a00080117 |
12 | 32976443a21 |
13 | 15b59037332 |
14 | 99941aa249 |
15 | 531bcb53d1 |
hex | 2e9d862df9 |
200211312121 has 8 divisors (see below), whose sum is σ = 207136918080. Its totient is φ = 193287157392.
The previous prime is 200211312109. The next prime is 200211312163. The reversal of 200211312121 is 121213112002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 200211312121 - 221 = 200209214969 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200211312095 and 200211312104.
It is not an unprimeable number, because it can be changed into a prime (200211312181) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78325 + ... + 637618.
It is an arithmetic number, because the mean of its divisors is an integer number (25892114760).
Almost surely, 2200211312121 is an apocalyptic number.
It is an amenable number.
200211312121 is a deficient number, since it is larger than the sum of its proper divisors (6925605959).
200211312121 is an equidigital number, since it uses as much as digits as its factorization.
200211312121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 725615.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 200211312121 its reverse (121213112002), we get a palindrome (321424424123).
The spelling of 200211312121 in words is "two hundred billion, two hundred eleven million, three hundred twelve thousand, one hundred twenty-one".
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